Welcome to the **Projectile Motion MDCAT** MCQs with Answers. In this post, we have shared **Projectile Motion** Multiple Choice Questions and Answers for **PMC MDCAT 2024**. Each question in MDCAT Physics offers a chance to enhance your knowledge regarding **Projectile Motion** MCQs in this MDCAT Online Test.

## Projectile Motion MDCAT MCQs Test Preparations

What is the shape of the trajectory of a projectile?

a) Straight line

b) Parabola

c) Circle

d) Ellipse

The horizontal component of the velocity of a projectile remains:

a) Zero

b) Constant

c) Increasing

d) Decreasing

The range of a projectile is maximum when the angle of projection is:

a) 30°

b) 45°

c) 60°

d) 90°

If a projectile is launched with an initial velocity of 20 m/s at an angle of 30°, what is the horizontal component of the velocity?

a) 10 m/s

b) 17.32 m/s

c) 15 m/s

d) 20 m/s

The vertical component of the velocity of a projectile at the highest point of its trajectory is:

a) Zero

b) Equal to the horizontal component

c) Maximum

d) The same as the initial vertical component

For a given initial velocity, increasing the angle of projection from 30° to 60° will:

a) Increase the range

b) Decrease the range

c) Not affect the range

d) Increase the time of flight

The time of flight of a projectile is independent of:

a) The initial velocity

b) The angle of projection

c) The horizontal range

d) The acceleration due to gravity

The horizontal distance covered by a projectile before it hits the ground is called:

a) Maximum height

b) Time of flight

c) Horizontal range

d) Vertical displacement

The angle of projection for a projectile to achieve maximum range is:

a) 30°

b) 45°

c) 60°

d) 90°

A projectile is launched with an initial velocity of 30 m/s at an angle of 45°. What is the time of flight?

a) 6 s

b) 3 s

c) 4 s

d) 5 s

The vertical motion of a projectile is similar to:

a) Uniform circular motion

b) Uniform motion

c) Free fall

d) Simple harmonic motion

At the maximum height of its trajectory, the kinetic energy of a projectile is:

a) Maximum

b) Zero

c) Equal to its potential energy

d) Half of the total energy

The vertical component of the velocity of a projectile just before hitting the ground is:

a) The same as it was at launch

b) Zero

c) Equal to the horizontal component

d) Half of the initial vertical component

The trajectory of a projectile is symmetrical with respect to:

a) Maximum height

b) The horizontal distance

c) The point of launch

d) The time of flight

The time to reach the maximum height of a projectile is equal to:

a) The total time of flight divided by 2

b) The maximum height divided by the initial velocity

c) The horizontal range divided by the horizontal component of velocity

d) The vertical component of velocity divided by gravity

The angle of projection for a given range is always:

a) 45°

b) Less than 45°

c) More than 45°

d) Either 45° or complementary to 45°

The horizontal distance covered by a projectile when it returns to the same level from which it was projected is called:

a) Maximum height

b) Range

c) Time of flight

d) Vertical displacement

The horizontal motion of a projectile is:

a) Accelerated motion

b) Uniform motion

c) Variable motion

d) Non-uniform motion

The trajectory of a projectile is a parabola because:

a) The horizontal velocity is constant

b) The vertical velocity is constant

c) The acceleration is constant

d) The vertical acceleration is constant

When a projectile is launched at an angle

𝜃

θ, the horizontal range is independent of:

a) The launch velocity

b) The launch angle

c) The acceleration due to gravity

d) The height from which it is launched

If the angle of projection is 90°, the projectile motion becomes:

a) Horizontal motion

b) Free fall

c) Uniform motion

d) Uniform circular motion

For a projectile, the total mechanical energy is:

a) Only potential energy

b) Only kinetic energy

c) The sum of kinetic and potential energy

d) Constant

At the maximum height, the projectile’s potential energy is:

a) Zero

b) Maximum

c) Half of the total energy

d) Equal to the kinetic energy

The distance traveled by a projectile in the horizontal direction is equal to:

a) The horizontal component of velocity multiplied by time of flight

b) The vertical component of velocity multiplied by time of flight

c) The initial velocity multiplied by the vertical component

d) The initial velocity multiplied by the horizontal range

For a projectile launched at an angle of 45°, the horizontal range is:

a) Maximum

b) Minimum

c) The same as for any other angle

d) Twice the height

The time of flight of a projectile depends on:

a) The angle of projection

b) The horizontal component of velocity

c) The vertical component of velocity

d) The initial velocity and angle of projection

The height of a projectile can be calculated by:

a) Using the vertical component of the velocity

b) Using the horizontal range

c) Multiplying the initial velocity by time of flight

d) Subtracting the horizontal range from the maximum height

If the projectile is launched with the same speed but at different angles, the maximum height achieved will be:

a) The same for all angles

b) Maximum for a 45° angle

c) Maximum for a 90° angle

d) Minimum for a 90° angle

The horizontal distance covered by a projectile in the time of flight is its:

a) Maximum height

b) Vertical displacement

c) Range

d) Time of flight

A projectile with a higher launch speed will have:

a) A lower maximum height

b) A smaller range

c) A longer time of flight

d) A shorter time of flight

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