Welcome to the **Acceleration MDCAT** MCQs with Answers. In this post, we have shared **Acceleration** Multiple Choice Questions and Answers for PMC MDCAT** 2024**. Each question in MDCAT Physics offers a chance to enhance your knowledge regarding **Acceleration** MCQs in this MDCAT Online Test.

## Acceleration MDCAT MCQs Test Preparations

Acceleration is defined as:

a) The rate of change of distance

b) The rate of change of velocity

c) The total distance traveled divided by time

d) The speed of an object

If an object’s velocity increases from 20 m/s to 30 m/s in 5 seconds, its acceleration is:

a) 2 m/s²

b) 10 m/s²

c) 5 m/s²

d) 1 m/s²

An object experiencing constant acceleration will have a velocity-time graph that is:

a) A straight line with a positive slope

b) A horizontal line

c) A vertical line

d) A curved line

The unit of acceleration is:

a) m/s

b) m/s²

c) km/h

d) m

Acceleration can be calculated by:

a) Change in distance / Time

b) Change in velocity / Time

c) Velocity / Time

d) Distance / Time

If a car decelerates from 60 m/s to 20 m/s in 8 seconds, its acceleration is:

a) -5 m/s²

b) -10 m/s²

c) 5 m/s²

d) 10 m/s²

The acceleration due to gravity near the Earth’s surface is approximately:

a) 9.8 m/s²

b) 10 m/s²

c) 9.8 km/h²

d) 10 km/h²

An object in free fall has an acceleration equal to:

a) The acceleration due to gravity

b) Zero

c) The object’s velocity

d) The change in speed

If an object’s velocity decreases from 40 m/s to 10 m/s in 6 seconds, its acceleration is:

a) -5 m/s²

b) -10 m/s²

c) 5 m/s²

d) 10 m/s²

If an object accelerates at 4 m/s² for 5 seconds, its change in velocity is:

a) 20 m/s

b) 4 m/s

c) 5 m/s

d) 2 m/s

Uniform acceleration means:

a) The object’s velocity is changing at a constant rate

b) The object’s velocity is constant

c) The object’s speed is increasing

d) The object is at rest

If an object’s velocity changes by 15 m/s in 3 seconds, its acceleration is:

a) 5 m/s²

b) 45 m/s²

c) 10 m/s²

d) 3 m/s²

A car increases its velocity from 20 m/s to 50 m/s in 6 seconds. The average acceleration is:

a) 5 m/s²

b) 3.33 m/s²

c) 10 m/s²

d) 30 m/s²

Acceleration is a vector quantity because:

a) It has magnitude only

b) It has both magnitude and direction

c) It only affects speed

d) It is always positive

The formula for acceleration when initial and final velocities and time are known is:

a) a = (v – u) / t

b) a = (u + v) / t

c) a = u / t

d) a = v / t

If an object’s acceleration is zero, the object:

a) Is at rest

b) Is moving with constant velocity

c) Is accelerating uniformly

d) Has a changing velocity

The acceleration of an object moving in a straight line with constant velocity is:

a) Zero

b) Constant

c) Increasing

d) Decreasing

If a car’s acceleration is 3 m/s², what is its change in velocity after 4 seconds?

a) 12 m/s

b) 7 m/s

c) 8 m/s

d) 15 m/s

In a velocity-time graph, the area under the curve represents:

a) Displacement

b) Acceleration

c) Speed

d) Time

If an object starts from rest and accelerates at 6 m/s² for 10 seconds, its final velocity is:

a) 60 m/s

b) 6 m/s

c) 100 m/s

d) 30 m/s

The acceleration of an object is defined as:

a) Change in distance divided by time

b) Change in velocity divided by time

c) Speed divided by distance

d) Distance divided by time

If an object’s acceleration is negative, it indicates:

a) The object is speeding up

b) The object is slowing down

c) The object is at rest

d) The object is moving at constant velocity

The acceleration due to gravity on the Moon is approximately:

a) 1.6 m/s²

b) 9.8 m/s²

c) 10 m/s²

d) 5 m/s²

An object accelerating uniformly will have a velocity-time graph that is:

a) A horizontal line

b) A straight line with a constant slope

c) A curve

d) A vertical line

If a car travels with an acceleration of 4 m/s², what will be its velocity after 3 seconds if it started from rest?

a) 12 m/s

b) 7 m/s

c) 4 m/s

d) 3 m/s

In a situation where the acceleration is constant, the velocity-time graph will be:

a) A horizontal line

b) A vertical line

c) A straight line with a slope

d) A curve

An object accelerating at -3 m/s² is:

a) Speeding up

b) Slowing down

c) Moving with constant velocity

d) At rest

The area under an acceleration-time graph represents:

a) Velocity

b) Displacement

c) Acceleration

d) Time

If an object has an initial velocity of 5 m/s and accelerates at 2 m/s² for 4 seconds, its final velocity is:

a) 13 m/s

b) 15 m/s

c) 9 m/s

d) 7 m/s

Acceleration is:

a) The rate of change of speed

b) The rate of change of displacement

c) The rate of change of velocity

d) The total distance divided by time

If an object’s velocity changes by 8 m/s in 4 seconds, its acceleration is:

a) 2 m/s²

b) 8 m/s²

c) 4 m/s²

d) 1 m/s²

The final velocity of an object accelerating uniformly can be calculated using the formula:

a) v = u + at

b) v = u – at

c) v = at

d) v = u / t

If a ball is thrown upwards with an initial velocity of 20 m/s and acceleration due to gravity is -9.8 m/s², the time to reach the highest point is:

a) 2 seconds

b) 1 second

c) 4 seconds

d) 5 seconds

An object that is accelerating has:

a) A constant velocity

b) A changing velocity

c) A constant speed

d) Zero displacement

If an object accelerates from rest to 20 m/s in 4 seconds, its acceleration is:

a) 5 m/s²

b) 4 m/s²

c) 20 m/s²

d) 10 m/s²

Acceleration can be positive, negative, or:

a) Zero

b) Constant

c) Varying

d) Uniform

The rate at which an object’s velocity changes is called:

a) Speed

b) Displacement

c) Acceleration

d) Force

If an object travels with an acceleration of 0 m/s², it is:

a) Accelerating uniformly

b) Moving with constant velocity

c) At rest

d) Speeding up

The acceleration of a body moving with a uniform velocity is:

a) Positive

b) Zero

c) Negative

d) Variable

If an object has an initial velocity of 10 m/s and accelerates at 3 m/s² for 5 seconds, its final velocity is:

a) 25 m/s

b) 15 m/s

c) 20 m/s

d) 35 m/s

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